Question

3x² -4x-4=0
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Answer 1

3x² -4x-4=0

Δ = (-4)²-4·3·(-4)
Δ = 16+48
Δ = 64
    ↓
x₁ = (4 + √64) /6
x₁ = 2
    ↓
x₂ =  (4 - √64) /6
x₂ =  -2/3

Answer 2

$3 {x}^{2} - 4x - 4 = 0$

$a = 3$

$b = - 4$

$c = - 4$

$\Delta = {b}^{2} - 4ac$

$\Delta = {( - 4)}^{2} - 4 \times 3 \times ( - 4)$

$\Delta = 16 + 48$

$\Delta = 64 > 0 = > \exists \: x_{1} \: \neq \: x_{2}$

$x_{1,2}=\frac{-b\pm\sqrt{\Delta}}{2a}$

$x_{1,2}=\frac{-( - 4)\pm\sqrt{64}}{2 \times 3}$

$x_{1,2}=\frac{4\pm8}{6}$

$x_{1}=\frac{4 + 8}{6}$

$x_{1}=\frac{12}{6}$

$x_{1}=2$

$x_{2}=\frac{4 - 8}{6}$

$x_{2}= - \frac{4}{6}$

$x_{2}= - \frac{2}{3}$