Question

4/13
Calculează:
a) 3+3x[3+3:3x(3+3x3)]:15
b) 812-4x[6x(61-3 600:12:30)]:9
c) [214+240:(16-2x5)}x25-25:25
d) 90+7x[1 614-12.000:(18-10)]-16
e) 44+8x[280:(37-1.480:20:37)]:32-7
f) (18x8+56):[50x40:(220-2x60)]

Answer 1

a)3x3+[3+3:3x(3+3x3)]:15=

=9+[3+1x(3+9)]:15=

=9+(3+12):15=

=9+15:15=

=9+1=10

b)812-4x[6x(61-3600:12:30)]:9=

=812-4x[6x(61-300:30)]:9=

=812-4x[6x(61-10)]:9=

=812-4x(6x51):9=

=812-4x306:9=

=812-136=676

c)[214+240:(16-2x5)]x25-25:25=

=[214+240:(16-10)]x25-1=

=(214+240:6)x25-1=

=(214+40)x25-1=

=254x25-1=

=6350-1=6349

d)90+7x[161412000:(18-10)]-16=

=90+7x(161412000:8)-16=

=74+7x20176500=

=74+141235500=141235574

e)44+8x[280:(37-1480:20:37)]:32-7=

=44+8x[280:(37-2)]:32-7=

=44+8x(280:35):32-7=

=44+8x8:32-7=

=44+64:32-7=

=44+2-7=39

f)18x8+560:[5x40:(220-2x60)]=

=144+560:[200:(220-120)]=

=144+560:(200:100)=

=144+560:2=

=144+280=424