Question

4,2÷3-0,3×{[(20÷x-4)×0,2+5]-2.5÷0,25} =0,5.​

Answer 1

Explicație pas cu pas:

A) 5*(11,3-2,4*3,5)+11=

5*(11,3-8,4)+11=

5*2,9+11=

14,5+11=25,5

B) [13,4+0,5*(147,8-1,25*100)]*10-13,41=

[13,4+0,5*(147,8-125)]*10-13,41=

(13,4+0,5*22,8)*10-13,41=

(13,4+11,4)*10-13,41=

24,8*10-13,41=

248-13,41=234,59

C) 11*(48-12*3,4)+5*[19+4*(8,3-5,4)]-20,3=

11*(48-40,8)+5*(19+4*2,9)-20,3=

11*7,2+5*(19+11,6)-20,3=

79,2+5*30,6-20,3=

79,2+153-20,3=

232,2-20,3=211,9

D) [21:(2+0,5³ :1,25):10+0,5]:1,5*7,2=

[21:(2+0,125 :1,25):10+0,5]:10,8=

[21:(2+0,1):10+0,5]:10,8=

(21:2,1:10+0,5):10,8=

(1+0,5):10,8=

1,5:10,8=0,1389

E) [0,2⁸ *(2:0,2-0,5*20)]:5=

[0,2⁸ *(10-10)]:5=

0,2⁸*0:5=0

F) {3+0,5*[2,3-0,2*(3,1-5,12:3,2)]}:4=

{3+0,5*[2,3-0,2*(3,1-1,6)]}:4=

[3+0,5*(2,3-0,2*1,5)]:4=

[3+0,5*(2,3-0,3)]:4=

(3+0,5*2):4=

(3+1):4=

4:4=1