Question

(4×-3)²-(3×+2)²-7×(×-1)​

Answer 1

${(4x - 3)}^{2} = {(4x)}^{2} - 2 \times 4x \times 3 + {3}^{2} = {16x}^{2} - 24x + 9$

${(3x + 2)}^{2} + 2 \times 3x \times 2 + {2}^{2} = {3x}^{2} + 2 \times 3x \times 2 + {2}^{2} = {9 x}^{2} + 12x + 4$

$7x(x - 1) = {7x}^{2} - 7x$

${16x}^{2} - 24x + 9 - {9x}^{2} + 12x + 4 - {7x}^{2} - 7x = - 5x + 13$