Question

4,5,8 urgent va rogggg!!!!​

Answer 1

Răspuns:

4. a)40

   b)54

   c)24

5. a)320

   b)112

   c)321

8. a)39

   b)3

   c)6

   d)4

Explicație pas cu pas:

4. a) $12^{2}$-$2^{3}$ x 13=

       $2^{2}$ x $6^{2}$ - $2^{3}$ x 13=

      $2^{2}$  x(36-2 x 13)=

       $2^{2}$  x (36-26)=

       4 x 10=40

 b)$15^{2}$- 19 x $3^{2}$=

    $3^{2}$ x$5^{2}$ - 19 x

    $3^{2}$ x ( $5^{2}$ - 19 )=

    $3^{2}$ x(25-19)=

    9 x 6= 54

c)$18^{2}$- $5^{2}$ x 12=

   $3^{2}$ x $6^{2}$- 25 x 12=

  $3^{2}$ x $6^{2}$- 300=

  3 x (3 x $6^{2}$ - 100)=

  3 x (3 x 36 -100)=

  3 x (108-100)=

  3 x 8=24

5. a) $20^{2}$-80:$2^{4}$=

       $10^{2}$ x $2^{2}$-80:$2^{2}$ x =

       $2^{2}$ x ( $10^{2}$ -80:$2^{2}$ )=

       4 x (100-20)=

      4 x 80= 320

   b)$16^{2}$-72:$2^{3}$=

      $8^{2}$ x $2^{2}$- 72 :$2^{2}$ x 2=

      $2^{2}$  x ($8^{2}$-72:2)=

      4 x (64-36)=

      4 x 28= 112

  c) $18^{2}$-75:$5^{2}$=

     $3^{2}$ x $6^{2}$-75:25=

     $3^{2}$ x $6^{2}$-3=

     3 x (3 x $6^{2}$ - 1)=

     3 x (3 x 36-1)=

    3 x (108-1)=

    3 x 107 = 321

8. a) ($5^{0}$+$5^{1}$+$5^{2}$+$5^{3}$):$2^{2}$=

        (1+5+25+125):4=

        156:4=39

  b) ($7^{0}$+$7^{1}$+$7^{2}$-$3^{2}$):$2^{4}$=

       (1+7+49-9):16=

       48:16=3

  c) ($2^{0}$+$2^{1}$+$2^{2}$+$2^{3}$+$3^{2}$):$2^{2}$=

      (1+2+4+8+9):4=

     24:4=6

 d) ($3^{0}$+$3^{1}$+$3^{2}$+$3^{3}$-$2^{3}$):$2^{3}$=

     (1+3+9+27-8):8=

     32:8=4