Question

4,(629):(4-11supra9)-0,41(6)=xsupra24
rezolvati in multimea nr intregi

Answer 1

   
[tex]\displaystyle 4,(629):\left(4-\frac{11}{9}\right)-0,41(6)= \frac{x}{24} \\ \\ \frac{4629-4}{999} :\left( \frac{36}{9}-\frac{11}{9}\right)- \frac{416-41}{900}= \frac{x}{24} \\ \\ \frac{4625}{999} :\frac{25}{9}- \frac{375}{900}= \frac{x}{24} \\ \\ \frac{4625}{999} \times \frac{9}{25}- \frac{5}{12}= \frac{x}{24} \\ \\ \frac{185}{111}- \frac{5}{12}= \frac{x}{24} \\ \\ \frac{5}{3}- \frac{5}{12}= \frac{x}{24} [/tex]

[tex]\displaystyle \frac{20}{12}- \frac{5}{12}= \frac{x}{24} \\ \\ \frac{15}{12}= \frac{x}{24} \\ \\ x = \frac{15 \times 24}{12} = 15 \times 2 =\boxed{30}[/tex]

Answer 2

$\displaystyle 4,(629):\left(4- \frac{11}{9} \right )-0,41(6)= \frac{x}{24} \\ \\ \frac{4629-4}{999} : \frac{9 \cdot 4-11}{9} - \frac{416-41}{900} = \frac{x}{24} \\ \\ \frac{4625}{999} : \frac{36-11}{9} - \frac{375}{900} = \frac{x}{24} \\ \\ \frac{4625}{999} : \frac{25}{9} - \frac{375}{900} = \frac{x}{24} \\ \\ \frac{4625}{999} \cdot \frac{9}{25} - \frac{375}{900} = \frac{x}{24} \\ \\ \frac{41625}{24975} - \frac{375}{900} = \frac{x}{24}$

$\displaystyle \frac{166500}{99900} - \frac{41625}{99900} = \frac{x}{24} \\ \\ \frac{124875}{99900} = \frac{x}{24} \\ \\ 124875 \cdot 24=99900x \\ \\ 2997000=99900x \\ \\ x= \frac{2997000}{99900} \\ \\ \boxed{x=30}$