Question

(4+8+12+16+........+4000):(2+4+6+8+.......+2000)+(2011+37):2¹⁰

Answer 1

Răspuns:

Explicație pas cu pas:

(4+8+12+16+........+4000)=

4(1+2+3+....+1000)

(2+4+6+8+.......+2000)=

2(1+2+3+....+1000)

(4+8+12+16+........+4000):(2+4+6+8+.......+2000)+(2011+37):2¹⁰=

4(1+2+3+....+1000)/2(1+2+3+....+1000)+(2011+37):2¹⁰=

2+(2011+37)/2¹⁰=

(2^11+2048)/2^10=

(2^11+2^12)/2^10=

2^(11+12)/2^10=

2^(22-10)=2^12