Question

4.Calculati: a) [(1 supra 2)²- (1 supra 2)³]/ (-1 supra 2) la puterea  4; c) [(1 supra 2) la puterea 0 + (1 supra 2) la puterea 1+( 1 supra 2)² + (1 supra 2)³]/[1-(1 supra 2) la puterea 4]

Answer 1

[(1/2)²-(1/2)³:(-1/2)²·²]=
(1/2)²=1/2·1/2=1/4
(1/2)³=1/2·1/2·1/2=1/6
(-1/2)²·²=(-1/2)·(-1/2)·(-1/2)·(-1/2)=1/16 ( - cu - = +)
[1/4-1/6:1/16]=
[1/4-1/6·16/1]=   (se simplifica 6=3, 16=8)
[1/4-8/3]=    (1/4 se amplifica cu 3 si 8/3 se amplifica cu 4]
[3/12-32/12]=29/12