Question

4 la puterea 1000 - 2 la puterea 1999 - 64 la puterea 333 = 8 la puterea N ....

Answer 1

4^1000-2^1999-64^333=8^n
(2^2)^1000-2^1999-(2^6)^333=(2^3)^n
2^2000-2^1999-2^1998=2^3n
2^1998(2^2-2-1)=2^3n
2^1998*1=2^3n
3n=1998
n=666