Question

4 la puterea 37:(2x2 la puterea 71)+(3+3x105):106

Answer 1

$4^{37}:(2\cdot 2^{71})+(3+3\cdot 105):106=\\(2^2)^{37}:2^{1+71}+3\cdot(1+105):106=\\2^{74}:2^{72}+3\cdot 106:106=\\2^{74-72}+3=\\2^2+3= 4+3=\boxed{7}$