Question

(4 la puterea0 +4la puerea 1 +4 la puterea 2)totul la puterea5:21la puterea3-21la puterea 2

Answer 1

${ ({4}^{0} + {4}^{1} + {4}^{2}) }^{5} \div {21}^{3} - {21}^{2}$

$= {(1 + 4 + 16)}^{5} \div {21}^{3} - {21}^{2}$

$= {21}^{5} \div {21}^{3} - {21}^{2}$

$= {21}^{5 - 3} - {21}^{2}$

$= {21}^{2} - {21}^{2}$

$= 0$