Question

(4 m la pătrat - 1) x la pătrat + 4m x + 1 =0 ​

Answer 1

Răspuns:

(4m²-1)²x²+4mx+1=0

△ = b²-4ac

△ = (4m)²-4×(4m²-1)×1

△ = 16m²-16m²+4

△ =4

△ = 2²

x1=(-4m-√4)/[2×(4m²-1)]

x1=(-4m-2)/[2×(4m²-1)]

x1=2(-2m-1)/[2(4m²-1)]

x1=(-2m-1)/(4m²-1)

x1=-(2m+1)/[(2m-1)(2m+1)]

x1=-1/(2m-1)

x2=(-4m+√4)/[2×(4m²-1)]

x2=(-4m+2)/[2(2m-1)(2m+1)]

x2=-2(2m-1)/[2(2m-1)(2m+1)]

x2=-1/(2m+1)