Question

(4/rad3-3/rad8):1/rad24+rad27 este egal cu...
rad=radical
/=supra

Answer 1

(4/√3-3/√8):1/√24+√27=
=(4/√3-3/2√2):1/2√6+3√3=
=(4√3/3-3√2/4):√6/12+3√3=
=(16√3-9√2)/12x12/√6+3√3=
=(16√3-9√2)/√6+3√3=
=16√3/√6-9√2/√6+3√3=
=16√18/6-9√12/6+3√3=
=48√2/6-18√3/6+3√3=
=8√2-3√3+3√3=
=8√2

Answer 2

(4/√3-3/√8):1/√24+√27= =(4/√3-3/2√2):1/2√6+3√3= =(4√3/3-3√2/4):√6/12+3√3= =(16√3-9√2)/12x12/√6+3√3= =(16√3-9√2)/√6+3√3= =16√3/√6-9√2/√6+3√3= =16√18/6-9√12/6+3√3= =48√2/6-18√3/6+3√3= =8√2-3√3+3√3= =8√2