Question

4 radical 7-2(2 radical 7 +radical 3)+radical 12​

Answer 1

$\it 4 \sqrt{7} - 2 \: ( 2 \sqrt{7} + \sqrt{3} ) + \sqrt{12} = \\ \\ \it 4 \sqrt{7} - 4 \sqrt{7} - 2 \sqrt{3} + 2 \sqrt{3} = \\ \\ \it 0 + 0 = \\ \\ \boxed{ \it 0 }$

Answer 2

Explicație pas cu pas:

4√7-2(2√7+√3)+√12=

= 4√7-4√7-2√3+2√3=

=0