Question

4 (radical din)3×(13(radical din)3 +3(radical din)12) (radical din)=semnul de radical

Answer 1

4√3×(13√3+3√12)= 4√3(13√3+ 3×2√3) = 4√3( 13√3+6√3) = 4√3×19√3= 76×3= 228

sper ca nu am ratat ceva pe drum