Question

(4-radical3)la puterea a doua

Answer 1

$(4-\sqrt{3})^2 = 16-2 \cdot 4 \cdot \sqrt{3} + (\sqrt{3)}^2 = 16 - 8\sqrt{3} +3=19-8\sqrt{3}$

Answer 2

(4-rad 3 )^2=4^2- 2×rad3 ×4+(rad 3)^2=16-8rad 3 +3 = 19- 8rad 3