Question

4 si 5 (doar a si b)VA ROOOG!!!!DAU COROANA!!!!

Answer 1

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Answer 2

Răspuns:

4)

a)  AB= ((xB-xA)^2+(yB-yA)2)^0.5=2r2

AC = (4+9)^0.5 = r13

CD = (9+4)^0.5 = r13

BD = (16+49)^0.5= r65

AE = (1+4)^0.5= r5

CF = yF*r2=5r2

DE = (1+25)^0.5= r26

b)  M1 =  (x=xA+(xB-xA)/2 , y= yA+(yB-yA)/2)    => M1(2,4)

    M2 = (x=xD+(xA-xD)/2 , y= yD+(yA-yD)/2)   => M2(0.5 , 0.5)

    M3 = (x=xE+(xD-xE)/2 , y= yE+(yD-yE)/2)     => M3(-0.5 ,+0.5 )

5)  AB= (6^2+1^2)^0.5 = r37

     BC = ( 4^2+9^2)^0.5 = r97

     BE = (2^2+3^2)^0.5 = r13

xM=xA=-4   yM=-yA= -4

xN = - xA=4    yN = yA= 4

xP = -xA = +4   yP = -yA =-4

Explicație pas cu pas: