Question

4 supra19 x {1supra2 + 11supra5 :[1supra60+162(1supra270+1supra405+1supra360)]} =?

Answer 1

Amplificam 1/270 cu 12 , 1/405 cu 8 , 1/360 cu 9.
4/19*{1/2+ 11/5 : [ 1/60 + 162 * ( 12+8+9 / 3240 )]} = 
= 4/19* [ 1/2 + 11/5 : ( 1/60 + 162 * 29 / 3240 ) ] 
Simplificam 162 * 29 / 3240 cu 162
= 4/19*[1/2+11/5 : ( 1/60 + 29/20) ]
Amplificam 29/20 cu 3
= 4/19*[1/2+11/5 : ( 1/60 + 87/60)]
= 4/19 * ( 1/2 + 11/5 : 88/60) 
= 4/19 * (1/2 + 11/5 * 60/88 )
Simplificam 11/5 * 60/88 cu 11*5*4
= 4/19 * (1/2 + 3/2)
=4/19* 4/2
=4/19 * 2
=8/19