Question

4(x-1) totul la a doua - 7 mai mic sau egal (2x+5) totul la a doua

Answer 1

$4(x-1)^{2} -7 \leq (2x+5)^{2}$
Desfacem parantezele si efectuam calculele.
$4*(x^{2}-2x+1) -7 \leq (4x^{2}+20x+25)$
$4x^{2}-8x+4-7 \leq 4x^{2}+20x+25$
$-8x-3 \leq 20x + 25$
$-28 \leq 28x$
$-1 \leq x$
$x \geq -1$

Answer 2

4(x-1)² ≤(2x+5)²=
(4x-4)²≤4x²+25
16x²-16≤4x²+25
16x²-4x²≤25+16
12x≤41
x≤41:12
x≤3,416
x∈{3,2,1,0}