Question

408:[2×3²+(2⁵)⁴÷8⁶+1³+27¹³÷3³⁹]

Answer 1

Salut.

$=408:[2*9+2^{20} :(2^{3} )^{6} +1+(3^{3} )^{13}:3^{39}] =\\=408:(18+2^{20-18} +1+1)=408:(18+4+2)=408:24=17$