Question

[408-(302+c)+330]/6=4*3*6 ajutatima e pt nota de la mate

Answer 1

[408-(302+c)+330]:6=4x3x6
[408-(302+c)+330]:6=72
[408-(302+c)+330]=72x6
[408-(302+c)+330]=432
408-(302+c)=432-330
408-(302+c)=102
302+c=408-102
302+c=306
c=306-302
c=4

Succes la școală!

Answer 2

$[408-(302+c)+330]:6=4*3*6$
$[408-(302+c)+330]:6=72$
$[408-(302+c)+330]=72*6$
$[408-(302+c)+330]=432$
$408-(302+c)=432-330$
$408-(302+c)=102$
$302+c=408-102$
$302+c=306$
$c=306-302$
$c=4$