Question

(41^2-82+1):8:5-(2^6-2^5+2^2-2^0)

Answer 1

$( 41^{2} -82+1):8:5-( 2^{6}- 2^{5}+ 2^{2}- 2^{0})=$$( 41^{2} -81):8* \frac{1}{5}-( 64-32+4-1)= \frac{41^{2} -81}{8}* \frac{1}{5}-35=$$\frac{41^{2} -81}{40}-35=\frac{1681 -81}{40}-35=\frac{1600}{40}-35=40-35=5$