Question

(4²×12¹⁰-4×12¹⁰):12¹¹​

Answer 1

Explicație pas cu pas:

Dăm factor comun pe 12 la a 10a

Avem

[tex] {12}^{10} ( {4}^{2} - 4) \div {12}^{11} = {12}^{10} \times (16 - 4) \div {12}^{11} \\ = {12}^{10} \times 12 \div {12}^{11} = {12}^{10 - 11+1} = 1

Answer 2

 

$\displaystyle\bf\\\Big(4^2\times12^{10}-4\times12^{10}\Big):12^{11}=\\\\\\=\frac{4^2\times12^{10}-4\times12^{10}}{12^{11}}=\\\\\\=\frac{12^{10}\Big(4^2-4\Big)}{12^{11}}=\\\\\\=\frac{12^{10}\Big(16-4\Big)}{12^{11}}=\\\\\\=\frac{12^{10}\times12}{12^{11}}=\frac{12^{10+1}}{12^{11}}=\frac{12^{11}}{12^{11}}=\boxed{\bf1}$