Question

424-2x[a+1x(6x5-60:4-48:24)x8]=210​

Answer 1

Răspuns:

Explicație pas cu pas:

424-2x[a+1x(6x5-60:4-48:24)x8]=210​

2x[a+1x(6x5-60:4-48:24)x8] = 424 - 210 = 214

a+1x(6x5-60:4-48:24)x8 = 214 : 2 = 107

a = 107 - 1x(6x5-60:4-48:24)x8 = 107 - (30 - 15 - 2) x 8 = 107 - 13x8 = 107 - 104

a = 3

Answer 2

Răspuns:

Explicație pas cu pas:

424-2×[a+1×(6×5-60÷4-48÷24)×8]=210

424-2×[a+1×(30-15-2)×8]=210

424-2×[a+1×(15-2)×8]=210

424-2×(a+1×13×8)=210

424-2×(a+13×8)=210

424-2×(a+104)=210

2×(a+104)=424-210

2×(a+104)=214

a+104=214÷2

a+104=107

a=107-104

a=3

verificare

424-2×[3+1×(6×5-60÷4-48÷24)×8]=210

424-2×[3+1×(30-15-2)×8]=210

424-2×[3+1×(15-2)×8]=210

424-2×(3+1×13×8)=210

424-2×(3+13×8)=210

424-2×(3+104)=210

424-2×107=210

424-214=210