Question

{[(4³-8²)×3+3²]÷3+19}÷10²​

Answer 1

$((( {2}^{6} - {8}^{2}) \times 3 + {3}^{2} ) \div 3 + 19) + {10}^{2}$

$((( {2}^{6} - {2}^{6} ) \times 3 + {3}^{2} ) \div 3 + 19) \div {10}^{2}$

$((0 \times 3 + {3}^{2} ) \div 3 + 19 ) \div {10}^{2}$

$(( 0 + {3}^{2} ) \div 3 + 19) \div {10}^{2}$

$( {3}^{2} \div 3 + 19) \div {10}^{2}$

$(3 + 19) \div {10}^{2}$

$22 \div {10}^{2}$

$\frac{22}{ {10}^{2} }$

$\frac{22}{100}$

Simplifici fracția cu 2

$\frac{11}{50}$

Answer 2

{[(4^3 - 8^2) × 3 + 3^2] :3 + 19} : 10^2 =

= {[(64 - 64) × 3 + 9] : 3 + 19} : 10^2 =

= [(0 × 3 + 9) : 3 + 19] : 100 =

= (9 : 3 + 19) : 100 = 22 : 100 = 22/100 = 11/50 = 0,22