Question

[430-(64+x×7+2×11)]×(50-27×2+13×5-11×5)=1980
Catvestevx

Answer 1

[tex]\left(430-\left(64+x\cdot \:7+2\cdot \:11\right)\right)\left(50-27\cdot \:2+13\cdot \:5-11\cdot \:5\right)=1980 \\ \\ \frac{\left(430-\left(64+x\cdot \:7+2\cdot \:11\right)\right)\left(50-27\cdot \:2+13\cdot \:5-11\cdot \:5\right)}{6}=\frac{1980}{6} \\ \\ -7x+344=330 \\ \\ -7x+344-344=330-344 \\ \\ -7x=-14 \\ \\ \frac{-7x}{-7}=\frac{-14}{-7} \\ \\ x=2[/tex]