Question

432÷4+(19+2×(216-5×(a×b+1)))×10=2018
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Answer 1

Răspuns:

Explicație pas cu pas:

432÷4+(19+2×(216-5×(a×b+1)))×10=2018

​108 + (19 + 2 x (216 - 5 x (a x b + 1))) x 10 = 2018

(19 + 2 x (216 - 5 x (a x b + 1))) x 10 = 2018 - 108 = 1910

19 + 2 x (216 - 5 x (a x b + 1)) = 1910 : 10 = 191

2 x (216 - 5 x (a x b + 1)) = 191 - 19 = 172

216 - 5 x (a x b + 1) = 172 : 2 = 86

5 x (a x b + 1) = 216 - 86 = 130

a x b + 1 = 130 : 5 = 26

a x b = 26 - 1

a x b = 25

Cum nu ai pus cerinta, sper sa te descurci in caz ca se cereau a si b.