Question

440g de carbon se folosesc pentru
reducerea magnetitei (Fe3O4) de puritate 80%. Calculeaza:
,a)numarul de moli de gaz
B) masa de fier formata
C)masa de magnetita utilizata

Plz am nevoie de ajutor plz

Answer 1

M,magnetita= 232g/mol
A,Fe=56g/mol
A,C=12g/mol

ecuatia reactiei
1mol         2mol     3mol        2mol
Fe3O4  +2C--->   3Fe   +   2CO2
232g.......2x12g......3x56g.......2mol
x..............440g..............y...........z
a).   z=n,CO2= 440x2/24=.........................calculeaza
b).   y=m,Fe= 440x3x56/24=......................calculeaza.
c).   x=m,magnetita= 440x232/24= 42533,3g  pura
p/100=m,pur/m,impur
80/100= 42533,3/ m,impur......................calculeaza!