Question

√441+2+4+6+...+880 heeeelppppppppp

Answer 1

$\sqrt{441+2+6+...+880}= \sqrt{441+2(1+2+3+...+440)}=$$= \sqrt{441+2* \frac{440*441}{2} }= \sqrt{441+440*441}= \sqrt{441(440+1)} = \sqrt{ 441^{2} }=$$=441$