Question

(46 p)Urgent ex 2 a si ex 3 c

Answer 1

2) a )

2^15 + 2 × 4^7 =

2^15 + 2 × ( 2^2)^7 =

2^15 + 2 × 2^14 =

2^14 × ( 2^1 + 2 × 1) =

2^14 × ( 2 + 2) =

2^14 × 4 =

2^14 × 2^2 =

2^16 = (2^4)^4 = 16^4
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5^8 = (5^2)^4 = 25^4


25^4 > 16^4 => 5^8 > (2^15 + 2 × 4^7)
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3) c )


( 7^4 - 7^3) : ( 7^2 - 7) - 2^3 × 5 =

[ 7^3 × ( 7^1 - 1)] : [7× ( 7^1 - 1 )] - 8 × 5 =

(7^3 × 6) : ( 7 × 6) - 40 =

(7^3 : 7 )× (6 : 6) - 40 =

7^2 × 1 - 40 =

49 - 40 =

9
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