Question

√48-13 √12supra lui 25+ √4 8asupra lui 25

Answer 1

$\displaystyle \sqrt{48} - \frac{13 \sqrt{12} }{25} + \frac{ \sqrt{48} }{25}= 4 \sqrt{3} - \frac{13 \cdot 2 \sqrt{3} }{25} + \frac{4 \sqrt{3} }{25} = \\ \\ =4 \sqrt{3} - \frac{26 \sqrt{3} }{25} + \frac{4 \sqrt{3} }{25} = \frac{100 \sqrt{3} -26 \sqrt{3} +4 \sqrt{3} }{25} = \frac{78 \sqrt{3} }{25}$