Question

√48 - ( {16/√32} - {18/√243} ) * √6 = ?

Answer 1

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Answer 2

$4 \sqrt{3} - ( \frac{12 \cdot 2 \sqrt{3} }{6} - \frac{4 \cdot 3 \sqrt{2} }{6} ) = \\ \\ 4 \sqrt{3 } - ( \frac{24 \sqrt{3} }{6} - \frac{12 \sqrt{2} }{6} ) = \\ \\ 4 \sqrt{3 } - ( 4 \sqrt{3} - 2 \sqrt{2} ) = 4 \sqrt{3} - 4 \sqrt{3} + 2 \sqrt{2} = 2 \sqrt{2}$