Question

(4a-3)(4a+3) va rog ajutatima

Answer 1

(4a-3)(4a+3) =
(4a)² - 3² =
16a²-9 ( raspunsul )

Answer 2

(4a-3)(4a+3) = (4a)²-3²= 16a²-9 ⇒ 16a² = 9 ⇒ a² = $\frac{9}{16}$ ⇒ a = $\frac{ \sqrt{9} }{ \sqrt{16} }$ ⇒ a = $\frac{3}{4}$