Question

(4intregi 1/6)^12 : (11intregi 1/9)^6

Answer 1

4 intregi si 1/6 = 24/6 + 1/6 = 25/6
11 intregi si 1/9 = 99/9 + 1/9 = 100/9
Atunci:
   (4 intregi si 1/6) ^12: (11 intregi si1/9)^6 = 
= (25/6)^12 : (100/9)^6 =
= [(5^2)/2*3]^12 : [(2^2*5^2)/3^2]^6 =
= 5^24/(2^12*3^12) : (2^12*5^12)/3^12 = 
= 5^24/(2^12*3^12) x 3^12/(2^12*5^12) = 
= 5^12/2^24 = 
= 5^12/(2^2)^12 =
= 5^12/4^12 =
= (5/4)^12 = 
= (1 intreg si 1/4)^12