Question

4la n x9+16x 2la 2n este pp

Answer 1

4$4^{n} * 9 +16* 2^{2n} <=>$ 
4 se scrie ${ 2^{2}}^n$
<=>$2^{2n} *3 ^{2} +4 ^{2} *2 ^{2n}= 2 ^{2n}$(3²+4²)=$2^{2n} *25=2^{2n}*25$ =${(2^{n} )^2}* 5^{2}= (2 ^{2} *5)^{2}$