Question

[4la puterea7×(-4)la12÷(-4)la15]la12÷(-4)la44

Answer 1

[tex]\left[4^7\cdot(-4)^{12}:(-4)^{15}\right]^{12}:(-4)^{44}=(-4^7\cdot4^{12}:4^{15})^{12}:4^{44}= [/tex]

$(4^{7+12-15})^{12}:4^{44}=4^{48}:4^{44}=4^4=256$

Answer 2

$[4^7*(-4)^{12}:(-4)^{15}]^{12}:4^{44}=[4^7*4^{12}*(-1)^{12}:4^{15}:(-1)^{15}]^{12}:4^{44} \\ =[4^4:(-1)]^{12}:4^{44}=(-4^{4})^{12}:4^{44}=4^{48}:4^{44}=4^4=256$