Question

4puterea14-(6•4puterea13-2•2puterea26)

Answer 1

${4}^{14} - (6 \times {4}^{13} - 2 \times {2}^{26} )$

$= {( {2}^{2}) }^{14} - 6 \times {( {2}^{2} )}^{13} + {2}^{1 + 26}$

$= {2}^{2 \times 14} - 6 \times {2}^{2 \times 13} + {2}^{27}$

$={2}^{28}-6 \times {2}^{26}+{2}^{27}$

$={2}^{26}({2}^{2}-6+2)$

$={2}^{26}(4-6+2)$

$={2}^{26}(-2+2)$

$={2}^{26} \times 0$

$=0$

Answer 2

=(2²)¹⁴ − (3×2×(2²)¹³−2²⁷) =

= 2²⁸−(3×2²⁷−2²⁷) =

= 2²⁸ − 2²⁷× (3-1)=

= 2²⁸−2²⁷×2=

= 2²⁸−2²⁸= 0