Question

4radical 3×(2radical75-radical27+3radical12)-2radical3×48​

Answer 1

$= 4 \sqrt{3} \times (2 \sqrt{75} - 3 \sqrt{3} + 6 \sqrt{3} ) - 96 \sqrt{3} = 4 \sqrt{3} \times (2 \sqrt{75} - 3 \sqrt{3} + 6 \sqrt{3} - 24) = 4 \sqrt{3} \times (10 \sqrt{3} - 3 \sqrt{3} + 6 \sqrt{3 } - 24) = 4 \sqrt{3} \times (13 \sqrt{3} - 24)$