Question

(4x+1)totul la a doua - (2x+3)totul la a doua

Answer 1

$(4x+1)^{2} -(2x+3)^{2}$
$(4x+1)^{2}=16 x^{2} +8x+1$
$(2x+3)^{2}=4 x^{2} +12x+9$
$16 x^{2} +8x+1-4 x^{2} +12x+9=12 x^{2} +2x+10$