Question

[4x+20x^2:(-4x)]÷(-x)

Answer 1

[4x+20X^2:(-4x)]:(-x)=
[4x+20:(-4)Xx^2:x]:(-x)=
[4x+(-5x)]:(-x)=
-x:(-x)=
=1


Sper ca te-am ajutat ! :)

Answer 2

$[4x + 20 {x}^{2} \div ( - 4x) ] \div ( - x)$

$= (4x - 5x) \div ( - x)$

$= ( - x) \div ( - x)$

$= 1$