Question

4x[28+(n+2) :6]-5=(37-14)x5​

Answer 1

Salutare!

4x[28+(n+2):6]-5=(37-14)x5

4x[28+(n+2):6]-5=23×5

4x[28+(n+2):6]-5=115

4x[28+(n+2):6]=115+5

4x[28+(n+2):6]=120

[28+(n+2):6]=120:4

28+(n+2):6=30

(n+2):6=30-28

(n+2):6=2

(n+2)=2×6

n+2=12

n=12-2

n=10

Answer 2

Răspuns:

Explicație pas cu pas: