Question

4x+4y-4=
y²x+yx²=
3(x-y)+b(x-y)=
x²-9=
2√x² - 81/121=
x²-6x+9=
25x²+20x+4=
x²+9x+14=
x la 4 + x³ - 6x²=
9(x-3)-225=
(x²-7x)(x²-7x+4)+4=
Metode de descompunere

Answer 1

4x+4y-4=4(x+y-1)y²x+yx²=xy(y+x)
3(x-y)+b(x-y)=(x-y)(b+3)
x²-9=(x-3)(x+3)
x²-6x+9=x²-2·3x+3²=(x-3)²
25x²+20x+4=5²x²+2·10x+2=(5x+2)²

x⁴ + x³ - 6x²=x²(x²+x-6)
9(x-3)-225=9x-27-225=9x-252
(x²-7x)(x²-7x+4)+4=x⁴-7x³+4x²-7x³+48x²-28x+4=x⁴-14x³+52x²-28x+4