Question

4x la Puterea 2 -5x+1 _>0​

Answer 1

$\it 4x^2-5x+1=4x^2-x-4x+1=x(4x-1)-(4x-1)=(4x-1)(x-1)\\ \\ 4x^2-5x+1=0 \Rightarrow (4x-1)(x-1)=0 \Rightarrow x_1=\dfrac{1}{4},\ \ x_2=1\\ \\ 4x^2-5x+1\geq0 \Rightarrow x\in\mathbb{R}\setminus \Big(\dfrac{1}{4},\ \ 1\Big)$