Question

√4x²+4x+1 (aici se termina radical) + 2 = 7

Answer 1

√(4x²+4x+1)+2=7
√(4x²+4x+1)²=5²
4x²+4x+1=25
4x²+4x-24=0
x²+x-6=0
a=1
b=1
c=-6
∆=b²-4ac
∆=1²-4*1*(-6)=25

x1=(-b+√∆)/2a=(-1+5)/2=2
x2=(-b-√∆)/2a=(-1-5)/2=-3

S={-3;2}