Question

= 4x² = (8 +4√3)√7-453 cum calculez????va rog ajutor!!!!​

Answer 1

Răspuns:

x= ±\frac{\sqrt{\sqrt{7}\left(8+4\sqrt{3}\right)-453}}{2}

Explicație pas cu pas:

$\frac{4x^{2} }{4}$ = \frac{\left(8+4\sqrt{3}\right)\sqrt{7}}{4}-\frac{453}{4}

= x²=\frac{\sqrt{7}\left(8+4\sqrt{3}\right)-453}{4}

pentru x² = f(a) solutiile sunt x= ±√f(a)

x = ±\sqrt{\frac{\sqrt{7}\left(8+4\sqrt{3}\right)-453}{4}}

aplicam regula radicalilor: \sqrt[n]{\frac{a}{b}}=\frac{\sqrt[n]{a}}{\sqrt[n]{b}}

x = \frac{\sqrt{\sqrt{7}\left(8+4\sqrt{3}\right)-453}}{\sqrt{4}}

√4 = 2 ,

x = ±\frac{\sqrt{\sqrt{7}\left(8+4\sqrt{3}\right)-453}}{2}

Sper ca te-am ajutat! Bafta in continuare!