Question

4x2(patrat)-4x+1= ? 
9x2-6x+1=? 
9x2-12x+4=?
x2-2x-y2+1=? 
va roggg ajutati-ma 

Answer 1

4x²-4x+1=
a=4,   b=-4,   c=1
Δ=b²-4ac
Δ=(-4)²-4·4·1=16-16=0
x1=(-a+√Δ)/2a
x1=(-)(-4)+0/2·4=(4+0)/8=4/8 simpli=1/2
x2=(-a-√Δ)/2a
x2=(-)(-4)+0/8=4/8=1/2
x1=x2=1/2

9x²-12x+4=0
Δ=144-4·9·4=0
x1=x2=12/18=simplif=4/6=2/3

9x²-6x+1=
Δ=36-36=0
x1=x2=6/18=simplif=1/3

x²-2x-y²+1=
x(x-2)-y²+1
x1=0
x2=2
y²+1=0
y²=-1
y1=√-1=i
y2=-√-1=-i