Question

4xla a2a - 4x =8
Cat este x

Answer 1

Vei obtine o ecuatie de gradul 2 pe care o vei rezolva cu delta

4x^2-4x-8=0
(delta)=16+128=144

x1=(4+12)/8=2.
x2=(4-12)/8=-1.

Answer 2

$4x^{2}-4x=8$
$4x^{2}-4x-8=0$
$4(x^{2}-x-2)=0$
$4(x^{2}+x-2x-2)=0$
$4[x\cdot(x+1)-2(x+1)]=0$
$4(x-2)\cdot(x+1)=0$
$(x-2)\cdot(x+1)=0$

$x-2=0$
$x+1=0$

$x-2=0$
$x+2=0$

$x_{1}=-1$
$x_{2}=2$