Question

5[1 supra 3 +2 supra 9 :2supra 9:(1supra 2 +1 supra 3)]

Answer 1

5 × [ 1 / 3 + 2 / 9 : 2 / 9 : ( 1 / 2 + 1 / 3 ) ] =

= 5 × [ 1 / 3 + 2 / 9 × 9 / 2 : ( 3 / 6 + 2 / 6 ) ] =

= 5 × ( 1 / 3 + 1 : 5 / 6 ) =

= 5 × ( 1 / 3 + 1 × 6 / 5  ) =

= 5 × ( 5 / 15 + 18 / 15 ) =

= 5 × 23 / 15 =

= 23 / 3 = 7 intregi si 2 / 3 = 7,(6)