Question

(5+16i)/(16-5i)=a+bi
calculeaza a si b

Answer 1

Salut,

Știm că i² = --1 (minus 1).

$\dfrac{5+16i}{16-5i}=\dfrac{(16i+5)(16+5i)}{(16+5i)(16-5i)}=\dfrac{256i-80+80+25i}{256+25}=\dfrac{281i}{281}=i,\\\\deci\ a=0,\ b=1.\ A\ fost\ greu\ ?$

Green eyes.