Question

5 [2 (1x+2)-11]+4=29

Answer 1

5[2*(x+2)-11]+4=29 / -4

5[2(x+2)-11]=25 /:5

2(x+2)-11=5 /+11

2(x+2)=16 /:2

x+2=8 /-2

x=6

Answer 2

5 × [2 × ( 1 x + 2 ) - 11 ] + 4 = 29

5 × [2 × ( 1 x + 2 ) - 11 ]  = 29 - 4

5 × [2 × ( 1 x + 2 ) - 11 ]  = 25

2 × ( 1 x + 2 ) - 11 = 25 : 5

2 × ( 1 x + 2 ) - 11 = 5

2 × ( 1 x + 2 ) = 5 + 11

1 x + 2 = 16 : 2

x + 2 = 8

x = 8 - 2

x = 6 → numarul, aflat prin metoda mersului invers